(6x+1)=(3x^2+2x+9)

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Solution for (6x+1)=(3x^2+2x+9) equation: 



(6x+1)=(3x^2+2x+9)

We move all terms to the left:

(6x+1)-((3x^2+2x+9))=0

We get rid of parentheses

6x-((3x^2+2x+9))+1=0



We calculate terms in parentheses: -((3x^2+2x+9)), so:

(3x^2+2x+9)

We get rid of parentheses

3x^2+2x+9

Back to the equation:

-(3x^2+2x+9)



We get rid of parentheses

-3x^2+6x-2x-9+1=0

We add all the numbers together, and all the variables

-3x^2+4x-8=0

a = -3; b = 4; c = -8;
Δ = b2-4ac
Δ = 42-4·(-3)·(-8)
Δ = -80
Delta is less than zero, so there is no solution for the equation

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